Base | Representation |
---|---|
bin | 10000011111101010110… |
… | …010101011000100000001 |
3 | 11000100210122111011102121 |
4 | 100133222302223010001 |
5 | 122032414440112402 |
6 | 2224421352044241 |
7 | 144615400132105 |
oct | 20375262530401 |
9 | 4010718434377 |
10 | 1133515550977 |
11 | 3a77a2a83557 |
12 | 163824093681 |
13 | 82b755c3044 |
14 | 3cc1079b905 |
15 | 1e743059837 |
hex | 107eacab101 |
1133515550977 has 2 divisors, whose sum is σ = 1133515550978. Its totient is φ = 1133515550976.
The previous prime is 1133515550957. The next prime is 1133515550987. The reversal of 1133515550977 is 7790555153311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1030192520256 + 103323030721 = 1014984^2 + 321439^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1133515550977 is a prime.
It is not a weakly prime, because it can be changed into another prime (1133515550957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566757775488 + 566757775489.
It is an arithmetic number, because the mean of its divisors is an integer number (566757775489).
Almost surely, 21133515550977 is an apocalyptic number.
It is an amenable number.
1133515550977 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133515550977 is an equidigital number, since it uses as much as digits as its factorization.
1133515550977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2480625, while the sum is 52.
The spelling of 1133515550977 in words is "one trillion, one hundred thirty-three billion, five hundred fifteen million, five hundred fifty thousand, nine hundred seventy-seven".
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