Base | Representation |
---|---|
bin | 10000011111101100111… |
… | …011100000001011100001 |
3 | 11000100220010222111122201 |
4 | 100133230323200023201 |
5 | 122033003130421004 |
6 | 2224425112533201 |
7 | 144616314043642 |
oct | 20375473401341 |
9 | 4010803874581 |
10 | 1133551420129 |
11 | 3a7811252587 |
12 | 1638340b1201 |
13 | 82b7cb715ab |
14 | 3cc154576c9 |
15 | 1e7462926a4 |
hex | 107ecee02e1 |
1133551420129 has 2 divisors, whose sum is σ = 1133551420130. Its totient is φ = 1133551420128.
The previous prime is 1133551420039. The next prime is 1133551420163. The reversal of 1133551420129 is 9210241553311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1080504117729 + 53047302400 = 1039473^2 + 230320^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1133551420129 is a prime.
It is not a weakly prime, because it can be changed into another prime (1133551420189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566775710064 + 566775710065.
It is an arithmetic number, because the mean of its divisors is an integer number (566775710065).
Almost surely, 21133551420129 is an apocalyptic number.
It is an amenable number.
1133551420129 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133551420129 is an equidigital number, since it uses as much as digits as its factorization.
1133551420129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 37.
The spelling of 1133551420129 in words is "one trillion, one hundred thirty-three billion, five hundred fifty-one million, four hundred twenty thousand, one hundred twenty-nine".
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