Base | Representation |
---|---|
bin | 10000011111101100111… |
… | …110100001101000111001 |
3 | 11000100220012110202122011 |
4 | 100133230332201220321 |
5 | 122033003331300122 |
6 | 2224425141525521 |
7 | 144616323554113 |
oct | 20375476415071 |
9 | 4010805422564 |
10 | 1133552212537 |
11 | 3a7811743968 |
12 | 1638344138a1 |
13 | 82b8008b184 |
14 | 3cc155c23b3 |
15 | 1e74639c377 |
hex | 107ecfa1a39 |
1133552212537 has 2 divisors, whose sum is σ = 1133552212538. Its totient is φ = 1133552212536.
The previous prime is 1133552212501. The next prime is 1133552212543. The reversal of 1133552212537 is 7352122553311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 652881776121 + 480670436416 = 808011^2 + 693304^2 .
It is a cyclic number.
It is not a de Polignac number, because 1133552212537 - 215 = 1133552179769 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1133552212537.
It is not a weakly prime, because it can be changed into another prime (1133552212237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566776106268 + 566776106269.
It is an arithmetic number, because the mean of its divisors is an integer number (566776106269).
Almost surely, 21133552212537 is an apocalyptic number.
It is an amenable number.
1133552212537 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133552212537 is an equidigital number, since it uses as much as digits as its factorization.
1133552212537 is an evil number, because the sum of its binary digits is even.
The product of its digits is 189000, while the sum is 40.
Adding to 1133552212537 its reverse (7352122553311), we get a palindrome (8485674765848).
The spelling of 1133552212537 in words is "one trillion, one hundred thirty-three billion, five hundred fifty-two million, two hundred twelve thousand, five hundred thirty-seven".
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