Base | Representation |
---|---|
bin | 10000100000000111110… |
… | …010011000000001010011 |
3 | 11000102001112211221211112 |
4 | 100200013302120001103 |
5 | 122034414003342433 |
6 | 2224541530403535 |
7 | 144633425030402 |
oct | 20400762300123 |
9 | 4012045757745 |
10 | 1134002012243 |
11 | 3a7a22633061 |
12 | 16393ab905ab |
13 | 82c22317949 |
14 | 3cc5922b639 |
15 | 1e770aeb348 |
hex | 10807c98053 |
1134002012243 has 2 divisors, whose sum is σ = 1134002012244. Its totient is φ = 1134002012242.
The previous prime is 1134002012239. The next prime is 1134002012309. The reversal of 1134002012243 is 3422102004311.
It is a weak prime.
It is an emirp because it is prime and its reverse (3422102004311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1134002012243 - 22 = 1134002012239 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1134002012543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567001006121 + 567001006122.
It is an arithmetic number, because the mean of its divisors is an integer number (567001006122).
Almost surely, 21134002012243 is an apocalyptic number.
1134002012243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134002012243 is an equidigital number, since it uses as much as digits as its factorization.
1134002012243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 1134002012243 its reverse (3422102004311), we get a palindrome (4556104016554).
The spelling of 1134002012243 in words is "one trillion, one hundred thirty-four billion, two million, twelve thousand, two hundred forty-three".
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