Base | Representation |
---|---|
bin | 10101000111110101… |
… | …10010100000001110 |
3 | 1002021022021022110201 |
4 | 22203322302200032 |
5 | 141211022011024 |
6 | 5113132124114 |
7 | 551005452553 |
oct | 124372624016 |
9 | 32238238421 |
10 | 11340032014 |
11 | 489a174993 |
12 | 224590663a |
13 | 10b950071c |
14 | 798104a2a |
15 | 465859744 |
hex | 2a3eb280e |
11340032014 has 8 divisors (see below), whose sum is σ = 17108372520. Its totient is φ = 5637241176.
The previous prime is 11340032009. The next prime is 11340032051. The reversal of 11340032014 is 41023004311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 11340031982 and 11340032000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16386984 + ... + 16387675.
It is an arithmetic number, because the mean of its divisors is an integer number (2138546565).
Almost surely, 211340032014 is an apocalyptic number.
11340032014 is a deficient number, since it is larger than the sum of its proper divisors (5768340506).
11340032014 is a wasteful number, since it uses less digits than its factorization.
11340032014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32774834.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 11340032014 its reverse (41023004311), we get a palindrome (52363036325).
The spelling of 11340032014 in words is "eleven billion, three hundred forty million, thirty-two thousand, fourteen".
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