Base | Representation |
---|---|
bin | 10000100000000111110… |
… | …110111100101011111001 |
3 | 11000102001122002212012222 |
4 | 100200013312330223321 |
5 | 122034414310223001 |
6 | 2224542012213425 |
7 | 144633441152333 |
oct | 20400766745371 |
9 | 4012048085188 |
10 | 1134003211001 |
11 | 3a7a23281771 |
12 | 16393b46a275 |
13 | 82c2264747b |
14 | 3cc59460453 |
15 | 1e770c8661b |
hex | 10807dbcaf9 |
1134003211001 has 2 divisors, whose sum is σ = 1134003211002. Its totient is φ = 1134003211000.
The previous prime is 1134003210997. The next prime is 1134003211009. The reversal of 1134003211001 is 1001123004311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 674942759401 + 459060451600 = 821549^2 + 677540^2 .
It is an emirp because it is prime and its reverse (1001123004311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1134003211001 - 22 = 1134003210997 is a prime.
It is not a weakly prime, because it can be changed into another prime (1134003211009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567001605500 + 567001605501.
It is an arithmetic number, because the mean of its divisors is an integer number (567001605501).
Almost surely, 21134003211001 is an apocalyptic number.
It is an amenable number.
1134003211001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134003211001 is an equidigital number, since it uses as much as digits as its factorization.
1134003211001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1134003211001 its reverse (1001123004311), we get a palindrome (2135126215312).
The spelling of 1134003211001 in words is "one trillion, one hundred thirty-four billion, three million, two hundred eleven thousand, one".
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