Base | Representation |
---|---|
bin | 10101000111110101… |
… | …10100111110001001 |
3 | 1002021022021211100001 |
4 | 22203322310332021 |
5 | 141211022321441 |
6 | 5113132243001 |
7 | 551005524202 |
oct | 124372647611 |
9 | 32238254301 |
10 | 11340042121 |
11 | 489a181541 |
12 | 2245910461 |
13 | 10b95051c5 |
14 | 7981085a9 |
15 | 46585c731 |
hex | 2a3eb4f89 |
11340042121 has 2 divisors, whose sum is σ = 11340042122. Its totient is φ = 11340042120.
The previous prime is 11340042037. The next prime is 11340042149. The reversal of 11340042121 is 12124004311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6034959225 + 5305082896 = 77685^2 + 72836^2 .
It is a cyclic number.
It is not a de Polignac number, because 11340042121 - 215 = 11340009353 is a prime.
It is not a weakly prime, because it can be changed into another prime (11340012121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670021060 + 5670021061.
It is an arithmetic number, because the mean of its divisors is an integer number (5670021061).
Almost surely, 211340042121 is an apocalyptic number.
It is an amenable number.
11340042121 is a deficient number, since it is larger than the sum of its proper divisors (1).
11340042121 is an equidigital number, since it uses as much as digits as its factorization.
11340042121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 11340042121 its reverse (12124004311), we get a palindrome (23464046432).
The spelling of 11340042121 in words is "eleven billion, three hundred forty million, forty-two thousand, one hundred twenty-one".
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