113400433 has 2 divisors, whose sum is σ = 113400434. Its totient is φ = 113400432.

The previous prime is 113400407. The next prime is 113400451. The reversal of 113400433 is 334004311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97456384 + 15944049 = 9872^2 + 3993^2 .

It is an emirp because it is prime and its reverse (334004311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113400433 - 2⁹ = 113399921 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113400433.

It is not a weakly prime, because it can be changed into another prime (113400233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56700216 + 56700217.

It is an arithmetic number, because the mean of its divisors is an integer number (56700217).

Almost surely, 2^113400433 is an apocalyptic number.

It is an amenable number.

113400433 is a deficient number, since it is larger than the sum of its proper divisors (1).

113400433 is an equidigital number, since it uses as much as digits as its factorization.

113400433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 113400433 is about 10648.9639402150. The cubic root of 113400433 is about 484.0292098688.

Adding to 113400433 its reverse (334004311), we get a palindrome (447404744).

The spelling of 113400433 in words is "one hundred thirteen million, four hundred thousand, four hundred thirty-three".