Base | Representation |
---|---|
bin | 10101000111110101… |
… | …10101011111001011 |
3 | 1002021022021221020100 |
4 | 22203322311133023 |
5 | 141211022403420 |
6 | 5113132300443 |
7 | 551005533312 |
oct | 124372653713 |
9 | 32238257210 |
10 | 11340044235 |
11 | 489a183093 |
12 | 2245911723 |
13 | 10b9506160 |
14 | 798109279 |
15 | 46585d190 |
hex | 2a3eb57cb |
11340044235 has 24 divisors (see below), whose sum is σ = 21168083664. Its totient is φ = 5582790720.
The previous prime is 11340044231. The next prime is 11340044267. The reversal of 11340044235 is 53244004311.
It is a happy number.
It is not a de Polignac number, because 11340044235 - 22 = 11340044231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11340044199 and 11340044208.
It is not an unprimeable number, because it can be changed into a prime (11340044231) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9691761 + ... + 9692930.
It is an arithmetic number, because the mean of its divisors is an integer number (882003486).
Almost surely, 211340044235 is an apocalyptic number.
11340044235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11340044235 is a deficient number, since it is larger than the sum of its proper divisors (9828039429).
11340044235 is a wasteful number, since it uses less digits than its factorization.
11340044235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19384715 (or 19384712 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 11340044235 its reverse (53244004311), we get a palindrome (64584048546).
The spelling of 11340044235 in words is "eleven billion, three hundred forty million, forty-four thousand, two hundred thirty-five".
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