Base | Representation |
---|---|
bin | 110100110011100110… |
… | …0101101000010101001 |
3 | 101211201002002221220201 |
4 | 1221213030231002221 |
5 | 3324221014030121 |
6 | 124032342552201 |
7 | 11123112425206 |
oct | 1514714550251 |
9 | 354632087821 |
10 | 113400533161 |
11 | 4410270aaa3 |
12 | 19b89738661 |
13 | a902b7b5c6 |
14 | 56baa8ccad |
15 | 2e3a907e91 |
hex | 1a6732d0a9 |
113400533161 has 2 divisors, whose sum is σ = 113400533162. Its totient is φ = 113400533160.
The previous prime is 113400533093. The next prime is 113400533171. The reversal of 113400533161 is 161335004311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 104115283561 + 9285249600 = 322669^2 + 96360^2 .
It is a cyclic number.
It is not a de Polignac number, because 113400533161 - 219 = 113400008873 is a prime.
It is not a weakly prime, because it can be changed into another prime (113400533171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56700266580 + 56700266581.
It is an arithmetic number, because the mean of its divisors is an integer number (56700266581).
Almost surely, 2113400533161 is an apocalyptic number.
It is an amenable number.
113400533161 is a deficient number, since it is larger than the sum of its proper divisors (1).
113400533161 is an equidigital number, since it uses as much as digits as its factorization.
113400533161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 28.
Adding to 113400533161 its reverse (161335004311), we get a palindrome (274735537472).
The spelling of 113400533161 in words is "one hundred thirteen billion, four hundred million, five hundred thirty-three thousand, one hundred sixty-one".
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