Base | Representation |
---|---|
bin | 10000100000001000011… |
… | …100010010101010010101 |
3 | 11000102002022112012200010 |
4 | 100200020130102222111 |
5 | 122034424312002331 |
6 | 2224543002110433 |
7 | 144633620313564 |
oct | 20401034225225 |
9 | 4012068465603 |
10 | 1134013000341 |
11 | 3a7a28858631 |
12 | 1639427ab419 |
13 | 82c24694190 |
14 | 3cc5a88bbdb |
15 | 1e771a6be46 |
hex | 10808712a95 |
1134013000341 has 32 divisors (see below), whose sum is σ = 1634964105600. Its totient is φ = 695012569344.
The previous prime is 1134013000313. The next prime is 1134013000381. The reversal of 1134013000341 is 1430003104311.
It is not a de Polignac number, because 1134013000341 - 219 = 1134012476053 is a prime.
It is a super-2 number, since 2×11340130003412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1134013000381) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17668390 + ... + 17732456.
It is an arithmetic number, because the mean of its divisors is an integer number (51092628300).
Almost surely, 21134013000341 is an apocalyptic number.
It is an amenable number.
1134013000341 is a deficient number, since it is larger than the sum of its proper divisors (500951105259).
1134013000341 is a wasteful number, since it uses less digits than its factorization.
1134013000341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65925.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1134013000341 its reverse (1430003104311), we get a palindrome (2564016104652).
The spelling of 1134013000341 in words is "one trillion, one hundred thirty-four billion, thirteen million, three hundred forty-one", and thus it is an aban number.
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