1134014113 has 2 divisors, whose sum is σ = 1134014114. Its totient is φ = 1134014112.

The previous prime is 1134014093. The next prime is 1134014137. The reversal of 1134014113 is 3114104311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1084845969 + 49168144 = 32937^2 + 7012^2 .

It is a cyclic number.

It is not a de Polignac number, because 1134014113 - 2¹⁷ = 1133883041 is a prime.

It is not a weakly prime, because it can be changed into another prime (1134018113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567007056 + 567007057.

It is an arithmetic number, because the mean of its divisors is an integer number (567007057).

Almost surely, 2^1134014113 is an apocalyptic number.

It is an amenable number.

1134014113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134014113 is an equidigital number, since it uses as much as digits as its factorization.

1134014113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 1134014113 is about 33675.1260279750. The cubic root of 1134014113 is about 1042.8123194766.

Adding to 1134014113 its reverse (3114104311), we get a palindrome (4248118424).

The spelling of 1134014113 in words is "one billion, one hundred thirty-four million, fourteen thousand, one hundred thirteen".