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1134039325849 is a prime number
BaseRepresentation
bin10000100000001010000…
…000101101110010011001
311000102011011001200110221
4100200022000231302121
5122040003031411344
62224545342240041
7144634360136413
oct20401200556231
94012134050427
101134039325849
113a7a416a9351
1216394b586021
1382c29c807c1
143cc601819b3
151e77401c184
hex1080a02dc99

1134039325849 has 2 divisors, whose sum is σ = 1134039325850. Its totient is φ = 1134039325848.

The previous prime is 1134039325823. The next prime is 1134039325877. The reversal of 1134039325849 is 9485239304311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 999464071824 + 134575254025 = 999732^2 + 366845^2 .

It is an emirp because it is prime and its reverse (9485239304311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1134039325849 - 25 = 1134039325817 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1134039325796 and 1134039325805.

It is not a weakly prime, because it can be changed into another prime (1134039325649) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567019662924 + 567019662925.

It is an arithmetic number, because the mean of its divisors is an integer number (567019662925).

Almost surely, 21134039325849 is an apocalyptic number.

It is an amenable number.

1134039325849 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134039325849 is an equidigital number, since it uses as much as digits as its factorization.

1134039325849 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2799360, while the sum is 52.

The spelling of 1134039325849 in words is "one trillion, one hundred thirty-four billion, thirty-nine million, three hundred twenty-five thousand, eight hundred forty-nine".