Base | Representation |
---|---|
bin | 10000100000001101101… |
… | …100110010100010111011 |
3 | 11000102022110111210101112 |
4 | 100200031230302202323 |
5 | 122040114402230243 |
6 | 2224555432510535 |
7 | 144636041145503 |
oct | 20401554624273 |
9 | 4012273453345 |
10 | 1134101211323 |
11 | 3a7a73627873 |
12 | 16396824b44b |
13 | 82c39a3aa22 |
14 | 3cc68490a03 |
15 | 1e779693818 |
hex | 1080db328bb |
1134101211323 has 2 divisors, whose sum is σ = 1134101211324. Its totient is φ = 1134101211322.
The previous prime is 1134101211241. The next prime is 1134101211343. The reversal of 1134101211323 is 3231121014311.
It is a strong prime.
It is an emirp because it is prime and its reverse (3231121014311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1134101211323 - 210 = 1134101210299 is a prime.
It is not a weakly prime, because it can be changed into another prime (1134101211343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567050605661 + 567050605662.
It is an arithmetic number, because the mean of its divisors is an integer number (567050605662).
Almost surely, 21134101211323 is an apocalyptic number.
1134101211323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134101211323 is an equidigital number, since it uses as much as digits as its factorization.
1134101211323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 1134101211323 its reverse (3231121014311), we get a palindrome (4365222225634).
The spelling of 1134101211323 in words is "one trillion, one hundred thirty-four billion, one hundred one million, two hundred eleven thousand, three hundred twenty-three".
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