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113410440223 = 760011492223
BaseRepresentation
bin110100110011111001…
…0011111110000011111
3101211201202202021211221
41221213302133300133
53324231033041343
6124033335154211
711123262556603
oct1514762376037
9354652667757
10113410440223
1144108267353
1219b90b15967
13a904c39a82
1456bc10b503
152e3b7135ed
hex1a67c9fc1f

113410440223 has 4 divisors (see below), whose sum is σ = 113412008448. Its totient is φ = 113408872000.

The previous prime is 113410440217. The next prime is 113410440263. The reversal of 113410440223 is 322044014311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113410440223 is a prime.

It is a super-3 number, since 3×1134104402233 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113410440263) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 670111 + ... + 822112.

It is an arithmetic number, because the mean of its divisors is an integer number (28353002112).

Almost surely, 2113410440223 is an apocalyptic number.

113410440223 is a deficient number, since it is larger than the sum of its proper divisors (1568225).

113410440223 is an equidigital number, since it uses as much as digits as its factorization.

113410440223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1568224.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 113410440223 its reverse (322044014311), we get a palindrome (435454454534).

The spelling of 113410440223 in words is "one hundred thirteen billion, four hundred ten million, four hundred forty thousand, two hundred twenty-three".

Divisors: 1 76001 1492223 113410440223