1134113310331 has 4 divisors (see below), whose sum is σ = 1134599430672. Its totient is φ = 1133627189992.

The previous prime is 1134113310307. The next prime is 1134113310361. The reversal of 1134113310331 is 1330133114311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1134113310331 - 2²⁵ = 1134079755899 is a prime.

It is a super-2 number, since 2×1134113310331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1134113310296 and 1134113310305.

It is not an unprimeable number, because it can be changed into a prime (1134113310301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 243056671 + ... + 243061336.

It is an arithmetic number, because the mean of its divisors is an integer number (283649857668).

Almost surely, 2^{1134113310331} is an apocalyptic number.

1134113310331 is a deficient number, since it is larger than the sum of its proper divisors (486120341).

1134113310331 is an equidigital number, since it uses as much as digits as its factorization.

1134113310331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 486120340.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 1134113310331 its reverse (1330133114311), we get a palindrome (2464246424642).

The spelling of 1134113310331 in words is "one trillion, one hundred thirty-four billion, one hundred thirteen million, three hundred ten thousand, three hundred thirty-one".