1134113443130 has 16 divisors (see below), whose sum is σ = 2041417278504. Its totient is φ = 453642470400.

The previous prime is 1134113443093. The next prime is 1134113443147. The reversal of 1134113443130 is 313443114311.

It can be written as a sum of positive squares in 4 ways, for example, as 1130549472529 + 3563970601 = 1063273^2 + 59699^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1134113443093 and 1134113443102.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2019230 + ... + 2519030.

Almost surely, 2^{1134113443130} is an apocalyptic number.

1134113443130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1134113443130 is a deficient number, since it is larger than the sum of its proper divisors (907303835374).

1134113443130 is a wasteful number, since it uses less digits than its factorization.

1134113443130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 726721.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1134113443130 its reverse (313443114311), we get a palindrome (1447556557441).

The spelling of 1134113443130 in words is "one trillion, one hundred thirty-four billion, one hundred thirteen million, four hundred forty-three thousand, one hundred thirty".