11341141453 has 4 divisors (see below), whose sum is σ = 11555125308. Its totient is φ = 11127157600.

The previous prime is 11341141451. The next prime is 11341141499. The reversal of 11341141453 is 35414114311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 35414114311 = 61 ⋅580559251.

It can be written as a sum of positive squares in 2 ways, for example, as 9762032809 + 1579108644 = 98803^2 + 39738^2 .

It is a cyclic number.

It is not a de Polignac number, because 11341141453 - 2¹ = 11341141451 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11341141451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106991848 + ... + 106991953.

It is an arithmetic number, because the mean of its divisors is an integer number (2888781327).

Almost surely, 2^11341141453 is an apocalyptic number.

It is an amenable number.

11341141453 is a deficient number, since it is larger than the sum of its proper divisors (213983855).

11341141453 is an equidigital number, since it uses as much as digits as its factorization.

11341141453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 213983854.

The product of its digits is 2880, while the sum is 28.

Adding to 11341141453 its reverse (35414114311), we get a palindrome (46755255764).

The spelling of 11341141453 in words is "eleven billion, three hundred forty-one million, one hundred forty-one thousand, four hundred fifty-three".