Base | Representation |
---|---|
bin | 10101000111111110… |
… | …01111111110110011 |
3 | 1002021101110201110202 |
4 | 22203333033332303 |
5 | 141211321420311 |
6 | 5113213145415 |
7 | 551021422625 |
oct | 124377177663 |
9 | 32241421422 |
10 | 11341201331 |
11 | 489a8a3469 |
12 | 224618b26b |
13 | 10b981ca25 |
14 | 79832ac15 |
15 | 4659dae3b |
hex | 2a3fcffb3 |
11341201331 has 2 divisors, whose sum is σ = 11341201332. Its totient is φ = 11341201330.
The previous prime is 11341201301. The next prime is 11341201363. The reversal of 11341201331 is 13310214311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11341201331 - 210 = 11341200307 is a prime.
It is a super-2 number, since 2×113412013312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11341201301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670600665 + 5670600666.
It is an arithmetic number, because the mean of its divisors is an integer number (5670600666).
Almost surely, 211341201331 is an apocalyptic number.
11341201331 is a deficient number, since it is larger than the sum of its proper divisors (1).
11341201331 is an equidigital number, since it uses as much as digits as its factorization.
11341201331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11341201331 its reverse (13310214311), we get a palindrome (24651415642).
The spelling of 11341201331 in words is "eleven billion, three hundred forty-one million, two hundred one thousand, three hundred thirty-one".
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