Base | Representation |
---|---|
bin | 10000100000001111100… |
… | …011111000111000110001 |
3 | 11000102101122020222200221 |
4 | 100200033203320320301 |
5 | 122040200400314213 |
6 | 2225002510013041 |
7 | 144636600421240 |
oct | 20401743707061 |
9 | 4012348228627 |
10 | 1134132432433 |
11 | 3a7a8a211740 |
12 | 1639767a7181 |
13 | 82c4334c760 |
14 | 3cc6c69a957 |
15 | 1e77c2ae38d |
hex | 1080f8f8e31 |
1134132432433 has 32 divisors (see below), whose sum is σ = 1522927752192. Its totient is φ = 815665032000.
The previous prime is 1134132432431. The next prime is 1134132432437. The reversal of 1134132432433 is 3342342314311.
It is not a de Polignac number, because 1134132432433 - 21 = 1134132432431 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1134132432431) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9231258 + ... + 9353308.
It is an arithmetic number, because the mean of its divisors is an integer number (47591492256).
Almost surely, 21134132432433 is an apocalyptic number.
1134132432433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1134132432433 is a deficient number, since it is larger than the sum of its proper divisors (388795319759).
1134132432433 is a wasteful number, since it uses less digits than its factorization.
1134132432433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131365.
The product of its digits is 62208, while the sum is 34.
Adding to 1134132432433 its reverse (3342342314311), we get a palindrome (4476474746744).
The spelling of 1134132432433 in words is "one trillion, one hundred thirty-four billion, one hundred thirty-two million, four hundred thirty-two thousand, four hundred thirty-three".
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