1134134020733 has 4 divisors (see below), whose sum is σ = 1296153166560. Its totient is φ = 972114874908.

The previous prime is 1134134020729. The next prime is 1134134020751. The reversal of 1134134020733 is 3370204314311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1134134020733 - 2² = 1134134020729 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1134134020733.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1134104020733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81009572903 + ... + 81009572916.

It is an arithmetic number, because the mean of its divisors is an integer number (324038291640).

Almost surely, 2^{1134134020733} is an apocalyptic number.

It is an amenable number.

1134134020733 is a deficient number, since it is larger than the sum of its proper divisors (162019145827).

1134134020733 is an equidigital number, since it uses as much as digits as its factorization.

1134134020733 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 162019145826.

The product of its (nonzero) digits is 18144, while the sum is 32.

The spelling of 1134134020733 in words is "one trillion, one hundred thirty-four billion, one hundred thirty-four million, twenty thousand, seven hundred thirty-three".