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11341411057 is a prime number
BaseRepresentation
bin10101001000000000…
…00011001011110001
31002021101212101011101
422210000003023301
5141211400123212
65113221444401
7551023255234
oct124400031361
932241771141
1011341411057
11489aa26a99
122246270701
1310b9894322
1479838341b
15465a2d157
hex2a40032f1

11341411057 has 2 divisors, whose sum is σ = 11341411058. Its totient is φ = 11341411056.

The previous prime is 11341411019. The next prime is 11341411063. The reversal of 11341411057 is 75011414311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11309046336 + 32364721 = 106344^2 + 5689^2 .

It is an emirp because it is prime and its reverse (75011414311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11341411057 is a prime.

It is not a weakly prime, because it can be changed into another prime (11341411007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670705528 + 5670705529.

It is an arithmetic number, because the mean of its divisors is an integer number (5670705529).

Almost surely, 211341411057 is an apocalyptic number.

It is an amenable number.

11341411057 is a deficient number, since it is larger than the sum of its proper divisors (1).

11341411057 is an equidigital number, since it uses as much as digits as its factorization.

11341411057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1680, while the sum is 28.

Adding to 11341411057 its reverse (75011414311), we get a palindrome (86352825368).

The spelling of 11341411057 in words is "eleven billion, three hundred forty-one million, four hundred eleven thousand, fifty-seven".