Base | Representation |
---|---|
bin | 10101001000000011… |
… | …00011101100010001 |
3 | 1002021102121110101222 |
4 | 22210001203230101 |
5 | 141212000300403 |
6 | 5113234134425 |
7 | 551026522553 |
oct | 124401435421 |
9 | 32242543358 |
10 | 11341806353 |
11 | 48a0176a89 |
12 | 2246421415 |
13 | 10b99a2227 |
14 | 7984474d3 |
15 | 465aaa338 |
hex | 2a4063b11 |
11341806353 has 2 divisors, whose sum is σ = 11341806354. Its totient is φ = 11341806352.
The previous prime is 11341806341. The next prime is 11341806361. The reversal of 11341806353 is 35360814311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7070791744 + 4271014609 = 84088^2 + 65353^2 .
It is a cyclic number.
It is not a de Polignac number, because 11341806353 - 222 = 11337612049 is a prime.
It is not a weakly prime, because it can be changed into another prime (11341806313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670903176 + 5670903177.
It is an arithmetic number, because the mean of its divisors is an integer number (5670903177).
Almost surely, 211341806353 is an apocalyptic number.
It is an amenable number.
11341806353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11341806353 is an equidigital number, since it uses as much as digits as its factorization.
11341806353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 11341806353 in words is "eleven billion, three hundred forty-one million, eight hundred six thousand, three hundred fifty-three".
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