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11342013 = 323164377
BaseRepresentation
bin101011010001…
…000010111101
3210100020022120
4223101002331
510400421023
61043033153
7165256044
oct53210275
923306276
1011342013
116447471
12396b7b9
132471667
14171355b
15ee08e3
hexad10bd

11342013 has 8 divisors (see below), whose sum is σ = 15780288. Its totient is φ = 7232544.

The previous prime is 11342011. The next prime is 11342027. The reversal of 11342013 is 31024311.

11342013 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11342013 - 21 = 11342011 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11341983 and 11342001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11342011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 82120 + ... + 82257.

It is an arithmetic number, because the mean of its divisors is an integer number (1972536).

Almost surely, 211342013 is an apocalyptic number.

It is an amenable number.

11342013 is a deficient number, since it is larger than the sum of its proper divisors (4438275).

11342013 is a wasteful number, since it uses less digits than its factorization.

11342013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 164403.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 11342013 is about 3367.7905219892. The cubic root of 11342013 is about 224.6794645691.

Adding to 11342013 its reverse (31024311), we get a palindrome (42366324).

The spelling of 11342013 in words is "eleven million, three hundred forty-two thousand, thirteen".

Divisors: 1 3 23 69 164377 493131 3780671 11342013