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11342011 is a prime number
BaseRepresentation
bin101011010001…
…000010111011
3210100020022111
4223101002323
510400421021
61043033151
7165256042
oct53210273
923306274
1011342011
11644746a
12396b7b7
132471665
141713559
15ee08e1
hexad10bb

11342011 has 2 divisors, whose sum is σ = 11342012. Its totient is φ = 11342010.

The previous prime is 11341991. The next prime is 11342027. The reversal of 11342011 is 11024311.

11342011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (11024311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11342011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11341982 and 11342000.

It is not a weakly prime, because it can be changed into another prime (11342041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671005 + 5671006.

It is an arithmetic number, because the mean of its divisors is an integer number (5671006).

Almost surely, 211342011 is an apocalyptic number.

11342011 is a deficient number, since it is larger than the sum of its proper divisors (1).

11342011 is an equidigital number, since it uses as much as digits as its factorization.

11342011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 11342011 is about 3367.7902250586. The cubic root of 11342011 is about 224.6794513628.

Adding to 11342011 its reverse (11024311), we get a palindrome (22366322).

It can be divided in two parts, 113 and 42011, that added together give a palindrome (42124).

The spelling of 11342011 in words is "eleven million, three hundred forty-two thousand, eleven".