113421133044133 has 4 divisors (see below), whose sum is σ = 113421559912128. Its totient is φ = 113420706176140.

The previous prime is 113421133044091. The next prime is 113421133044139. The reversal of 113421133044133 is 331440331124311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113421133044133 - 2¹³ = 113421133035941 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113421133044139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213035191 + ... + 213566932.

It is an arithmetic number, because the mean of its divisors is an integer number (28355389978032).

Almost surely, 2^{113421133044133} is an apocalyptic number.

It is an amenable number.

113421133044133 is a deficient number, since it is larger than the sum of its proper divisors (426867995).

113421133044133 is an equidigital number, since it uses as much as digits as its factorization.

113421133044133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 426867994.

The product of its (nonzero) digits is 31104, while the sum is 34.

Adding to 113421133044133 its reverse (331440331124311), we get a palindrome (444861464168444).

The spelling of 113421133044133 in words is "one hundred thirteen trillion, four hundred twenty-one billion, one hundred thirty-three million, forty-four thousand, one hundred thirty-three".