Search a number
-
+
1134235147 is a prime number
BaseRepresentation
bin100001110011011…
…0000111000001011
32221001021010010011
41003212300320023
54310331011042
6304314332351
740051561003
oct10346607013
92831233104
101134235147
11532278721
12277a2a0b7
13150ca9576
14aa8d1003
1569899a17
hex439b0e0b

1134235147 has 2 divisors, whose sum is σ = 1134235148. Its totient is φ = 1134235146.

The previous prime is 1134235093. The next prime is 1134235163. The reversal of 1134235147 is 7415324311.

It is a strong prime.

It is an emirp because it is prime and its reverse (7415324311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1134235147 - 219 = 1133710859 is a prime.

It is a super-2 number, since 2×11342351472 = 2572978737380223218, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1134235177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567117573 + 567117574.

It is an arithmetic number, because the mean of its divisors is an integer number (567117574).

Almost surely, 21134235147 is an apocalyptic number.

1134235147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134235147 is an equidigital number, since it uses as much as digits as its factorization.

1134235147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10080, while the sum is 31.

The square root of 1134235147 is about 33678.4077266132. The cubic root of 1134235147 is about 1042.8800676059.

Adding to 1134235147 its reverse (7415324311), we get a palindrome (8549559458).

The spelling of 1134235147 in words is "one billion, one hundred thirty-four million, two hundred thirty-five thousand, one hundred forty-seven".