Base | Representation |
---|---|
bin | 10000100000010110000… |
… | …011100100110111011011 |
3 | 11000102200020022020022002 |
4 | 100200112003210313123 |
5 | 122040411244333311 |
6 | 2225021401351215 |
7 | 144642362562602 |
oct | 20402603446733 |
9 | 4012606266262 |
10 | 1134241402331 |
11 | 3a803577a404 |
12 | 1639a719850b |
13 | 82c5cab3c9b |
14 | 3cc7cd44a39 |
15 | 1e786b3693b |
hex | 108160e4ddb |
1134241402331 has 2 divisors, whose sum is σ = 1134241402332. Its totient is φ = 1134241402330.
The previous prime is 1134241402267. The next prime is 1134241402379. The reversal of 1134241402331 is 1332041424311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1134241402331 - 26 = 1134241402267 is a prime.
It is a super-2 number, since 2×11342414023312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1134241402294 and 1134241402303.
It is not a weakly prime, because it can be changed into another prime (1134241402531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567120701165 + 567120701166.
It is an arithmetic number, because the mean of its divisors is an integer number (567120701166).
Almost surely, 21134241402331 is an apocalyptic number.
1134241402331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134241402331 is an equidigital number, since it uses as much as digits as its factorization.
1134241402331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1134241402331 its reverse (1332041424311), we get a palindrome (2466282826642).
The spelling of 1134241402331 in words is "one trillion, one hundred thirty-four billion, two hundred forty-one million, four hundred two thousand, three hundred thirty-one".
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