Base | Representation |
---|---|
bin | 10000100000010110000… |
… | …011101100011001110001 |
3 | 11000102200020100210122102 |
4 | 100200112003230121301 |
5 | 122040411301330301 |
6 | 2225021402150145 |
7 | 144642363051602 |
oct | 20402603543161 |
9 | 4012606323572 |
10 | 1134241433201 |
11 | 3a80357a0618 |
12 | 1639a71b2355 |
13 | 82c5cac5056 |
14 | 3cc7cd51da9 |
15 | 1e786b40b6b |
hex | 108160ec671 |
1134241433201 has 2 divisors, whose sum is σ = 1134241433202. Its totient is φ = 1134241433200.
The previous prime is 1134241433173. The next prime is 1134241433233. The reversal of 1134241433201 is 1023341424311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1088216166976 + 46025266225 = 1043176^2 + 214535^2 .
It is an emirp because it is prime and its reverse (1023341424311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1134241433201 - 214 = 1134241416817 is a prime.
It is not a weakly prime, because it can be changed into another prime (1134241433251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567120716600 + 567120716601.
It is an arithmetic number, because the mean of its divisors is an integer number (567120716601).
Almost surely, 21134241433201 is an apocalyptic number.
It is an amenable number.
1134241433201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134241433201 is an equidigital number, since it uses as much as digits as its factorization.
1134241433201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1134241433201 its reverse (1023341424311), we get a palindrome (2157582857512).
The spelling of 1134241433201 in words is "one trillion, one hundred thirty-four billion, two hundred forty-one million, four hundred thirty-three thousand, two hundred one".
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