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11343031323 = 3131491951993
BaseRepresentation
bin10101001000001100…
…01110110000011011
31002021111220200202020
422210012032300123
5141212304000243
65113320305523
7551043114111
oct124406166033
932244820666
1011343031323
1148a0933358
1222469122a3
1310ba010970
14798685ab1
15465c4d283
hex2a418ec1b

11343031323 has 16 divisors (see below), whose sum is σ = 16396749600. Its totient is φ = 6933475584.

The previous prime is 11343031321. The next prime is 11343031339. The reversal of 11343031323 is 32313034311.

It is a happy number.

It is not a de Polignac number, because 11343031323 - 21 = 11343031321 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11343031293 and 11343031302.

It is not an unprimeable number, because it can be changed into a prime (11343031321) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 970186 + ... + 981807.

It is an arithmetic number, because the mean of its divisors is an integer number (1024796850).

Almost surely, 211343031323 is an apocalyptic number.

11343031323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11343031323 is a deficient number, since it is larger than the sum of its proper divisors (5053718277).

11343031323 is a wasteful number, since it uses less digits than its factorization.

11343031323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1952158.

The product of its (nonzero) digits is 1944, while the sum is 24.

Adding to 11343031323 its reverse (32313034311), we get a palindrome (43656065634).

The spelling of 11343031323 in words is "eleven billion, three hundred forty-three million, thirty-one thousand, three hundred twenty-three".

Divisors: 1 3 13 39 149 447 1937 5811 1951993 5855979 25375909 76127727 290846957 872540871 3781010441 11343031323