113430333041131 has 4 divisors (see below), whose sum is σ = 113430562855200. Its totient is φ = 113430103227064.

The previous prime is 113430333041111. The next prime is 113430333041171. The reversal of 113430333041131 is 131140333034311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113430333041131 - 2⁴¹ = 111231309785579 is a prime.

It is a super-3 number, since 3×113430333041131³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113430333041093 and 113430333041102.

It is not an unprimeable number, because it can be changed into a prime (113430333041111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114165076 + ... + 115154353.

It is an arithmetic number, because the mean of its divisors is an integer number (28357640713800).

Almost surely, 2^{113430333041131} is an apocalyptic number.

113430333041131 is a deficient number, since it is larger than the sum of its proper divisors (229814069).

113430333041131 is an equidigital number, since it uses as much as digits as its factorization.

113430333041131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 229814068.

The product of its (nonzero) digits is 11664, while the sum is 31.

Adding to 113430333041131 its reverse (131140333034311), we get a palindrome (244570666075442).

The spelling of 113430333041131 in words is "one hundred thirteen trillion, four hundred thirty billion, three hundred thirty-three million, forty-one thousand, one hundred thirty-one".