113430333041171 has 2 divisors, whose sum is σ = 113430333041172. Its totient is φ = 113430333041170.

The previous prime is 113430333041111. The next prime is 113430333041183. The reversal of 113430333041171 is 171140333034311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113430333041171 is a prime.

It is a super-3 number, since 3×113430333041171³ (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (113430333041111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56715166520585 + 56715166520586.

It is an arithmetic number, because the mean of its divisors is an integer number (56715166520586).

Almost surely, 2^{113430333041171} is an apocalyptic number.

113430333041171 is a deficient number, since it is larger than the sum of its proper divisors (1).

113430333041171 is an equidigital number, since it uses as much as digits as its factorization.

113430333041171 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27216, while the sum is 35.

Adding to 113430333041171 its reverse (171140333034311), we get a palindrome (284570666075482).

The spelling of 113430333041171 in words is "one hundred thirteen trillion, four hundred thirty billion, three hundred thirty-three million, forty-one thousand, one hundred seventy-one".