Base | Representation |
---|---|
bin | 10000100000011010001… |
… | …001101011110001011011 |
3 | 11000102212000121001201111 |
4 | 100200122021223301123 |
5 | 122041031342043342 |
6 | 2225032254201151 |
7 | 144644155604416 |
oct | 20403211536133 |
9 | 4012760531644 |
10 | 1134310112347 |
11 | 3a807053a245 |
12 | 163a061b31b7 |
13 | 82c710c05b9 |
14 | 3cc8810cb7d |
15 | 1e78cbaa217 |
hex | 1081a26bc5b |
1134310112347 has 2 divisors, whose sum is σ = 1134310112348. Its totient is φ = 1134310112346.
The previous prime is 1134310112281. The next prime is 1134310112399. The reversal of 1134310112347 is 7432110134311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1134310112347 - 231 = 1132162628699 is a prime.
It is not a weakly prime, because it can be changed into another prime (1134310115347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567155056173 + 567155056174.
It is an arithmetic number, because the mean of its divisors is an integer number (567155056174).
Almost surely, 21134310112347 is an apocalyptic number.
1134310112347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134310112347 is an equidigital number, since it uses as much as digits as its factorization.
1134310112347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 1134310112347 its reverse (7432110134311), we get a palindrome (8566420246658).
The spelling of 1134310112347 in words is "one trillion, one hundred thirty-four billion, three hundred ten million, one hundred twelve thousand, three hundred forty-seven".
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