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11343214021411 is a prime number
BaseRepresentation
bin1010010100010000110000…
…1111100000101100100011
31111011101211002101110002001
42211010030033200230203
52441321400242141121
640043000043104431
72250343263215416
oct245041417405443
944141732343061
1011343214021411
1136836a2664098
121332483512117
13643878142b1c
142b302ba7db7d
1514a0e2abc991
hexa510c3e0b23

11343214021411 has 2 divisors, whose sum is σ = 11343214021412. Its totient is φ = 11343214021410.

The previous prime is 11343214021369. The next prime is 11343214021459. The reversal of 11343214021411 is 11412041234311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11343214021411 - 219 = 11343213497123 is a prime.

It is a super-2 number, since 2×113432140214112 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11343214021411.

It is not a weakly prime, because it can be changed into another prime (11343214024411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671607010705 + 5671607010706.

It is an arithmetic number, because the mean of its divisors is an integer number (5671607010706).

Almost surely, 211343214021411 is an apocalyptic number.

11343214021411 is a deficient number, since it is larger than the sum of its proper divisors (1).

11343214021411 is an equidigital number, since it uses as much as digits as its factorization.

11343214021411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 11343214021411 its reverse (11412041234311), we get a palindrome (22755255255722).

The spelling of 11343214021411 in words is "eleven trillion, three hundred forty-three billion, two hundred fourteen million, twenty-one thousand, four hundred eleven".