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11343241140302 = 25671620570151
BaseRepresentation
bin1010010100010000110111…
…0110111101100001001110
31111011101212222102020012102
42211010031312331201032
52441321424212442202
640043002452235102
72250344042554301
oct245041566754116
944141788366172
1011343241140302
1136837069a69a5
12133249060ba92
136438809495c6
142b30314dcb38
1514a0e5177d02
hexa510ddbd84e

11343241140302 has 4 divisors (see below), whose sum is σ = 17014861710456. Its totient is φ = 5671620570150.

The previous prime is 11343241140289. The next prime is 11343241140347. The reversal of 11343241140302 is 20304114234311.

11343241140302 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2835810285074 + ... + 2835810285077.

It is an arithmetic number, because the mean of its divisors is an integer number (4253715427614).

Almost surely, 211343241140302 is an apocalyptic number.

11343241140302 is a deficient number, since it is larger than the sum of its proper divisors (5671620570154).

11343241140302 is an equidigital number, since it uses as much as digits as its factorization.

11343241140302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5671620570153.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 11343241140302 its reverse (20304114234311), we get a palindrome (31647355374613).

The spelling of 11343241140302 in words is "eleven trillion, three hundred forty-three billion, two hundred forty-one million, one hundred forty thousand, three hundred two".

Divisors: 1 2 5671620570151 11343241140302