Base | Representation |
---|---|
bin | 110100110100100100… |
… | …0101101100101010011 |
3 | 101211210100021112121110 |
4 | 1221221020231211103 |
5 | 3324302324304420 |
6 | 124035503424403 |
7 | 11123655641013 |
oct | 1515110554523 |
9 | 354710245543 |
10 | 113433041235 |
11 | 44119aa3878 |
12 | 19b985b5103 |
13 | a909821057 |
14 | 56c1111c43 |
15 | 2e3d6c9ee0 |
hex | 1a6922d953 |
113433041235 has 16 divisors (see below), whose sum is σ = 191045122560. Its totient is φ = 57313536480.
The previous prime is 113433041213. The next prime is 113433041251. The reversal of 113433041235 is 532140334311.
It is a happy number.
It is not a de Polignac number, because 113433041235 - 212 = 113433037139 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 199005051 + ... + 199005620.
It is an arithmetic number, because the mean of its divisors is an integer number (11940320160).
Almost surely, 2113433041235 is an apocalyptic number.
113433041235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
113433041235 is a deficient number, since it is larger than the sum of its proper divisors (77612081325).
113433041235 is a wasteful number, since it uses less digits than its factorization.
113433041235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 398010698.
The product of its (nonzero) digits is 12960, while the sum is 30.
Adding to 113433041235 its reverse (532140334311), we get a palindrome (645573375546).
The spelling of 113433041235 in words is "one hundred thirteen billion, four hundred thirty-three million, forty-one thousand, two hundred thirty-five".
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