11343312334 has 4 divisors (see below), whose sum is σ = 17014968504. Its totient is φ = 5671656166.

The previous prime is 11343312319. The next prime is 11343312349. The reversal of 11343312334 is 43321334311.

11343312334 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43321334311 = 17 ⋅2548313783.

It is an interprime number because it is at equal distance from previous prime (11343312319) and next prime (11343312349).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2835828082 + ... + 2835828085.

It is an arithmetic number, because the mean of its divisors is an integer number (4253742126).

Almost surely, 2^11343312334 is an apocalyptic number.

11343312334 is a deficient number, since it is larger than the sum of its proper divisors (5671656170).

11343312334 is an equidigital number, since it uses as much as digits as its factorization.

11343312334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5671656169.

The product of its digits is 7776, while the sum is 28.

Adding to 11343312334 its reverse (43321334311), we get a palindrome (54664646645).

The spelling of 11343312334 in words is "eleven billion, three hundred forty-three million, three hundred twelve thousand, three hundred thirty-four".