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113433134101 = 7102191158573
BaseRepresentation
bin110100110100100100…
…1000100010000010101
3101211210100110020222221
41221221021010100111
53324302340242401
6124035505422341
711123656505530
oct1515111042025
9354710406887
10113433134101
114411a057621
1219b9863a9b1
13a9098543c1
1456c1137a17
152e3d6e77a1
hex1a69244415

113433134101 has 8 divisors (see below), whose sum is σ = 129639953664. Its totient is φ = 97226836080.

The previous prime is 113433134099. The next prime is 113433134153. The reversal of 113433134101 is 101431334311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113433134101 - 21 = 113433134099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113433134201) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 636051 + ... + 794623.

It is an arithmetic number, because the mean of its divisors is an integer number (16204994208).

Almost surely, 2113433134101 is an apocalyptic number.

It is an amenable number.

113433134101 is a deficient number, since it is larger than the sum of its proper divisors (16206819563).

113433134101 is a wasteful number, since it uses less digits than its factorization.

113433134101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 260771.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 113433134101 its reverse (101431334311), we get a palindrome (214864468412).

The spelling of 113433134101 in words is "one hundred thirteen billion, four hundred thirty-three million, one hundred thirty-four thousand, one hundred one".

Divisors: 1 7 102191 158573 715337 1110011 16204733443 113433134101