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113433203411014 = 256716601705507
BaseRepresentation
bin11001110010101010111001…
…110010111000100001000110
3112212122002220222110110201111
4121302222321302320201012
5104331442200033123024
61041130254431515234
732615164345151344
oct3162527162704106
9485562828413644
10113433203411014
113316382a145413
1210880146388b1a
134b3a922398a56
1420022a6a7a994
15d1a9d07eca94
hex672ab9cb8846

113433203411014 has 4 divisors (see below), whose sum is σ = 170149805116524. Its totient is φ = 56716601705506.

The previous prime is 113433203410999. The next prime is 113433203411029. The reversal of 113433203411014 is 410114302334311.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (113433203410999) and next prime (113433203411029).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28358300852752 + ... + 28358300852755.

It is an arithmetic number, because the mean of its divisors is an integer number (42537451279131).

Almost surely, 2113433203411014 is an apocalyptic number.

113433203411014 is a deficient number, since it is larger than the sum of its proper divisors (56716601705510).

113433203411014 is an equidigital number, since it uses as much as digits as its factorization.

113433203411014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56716601705509.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 113433203411014 its reverse (410114302334311), we get a palindrome (523547505745325).

The spelling of 113433203411014 in words is "one hundred thirteen trillion, four hundred thirty-three billion, two hundred three million, four hundred eleven thousand, fourteen".

Divisors: 1 2 56716601705507 113433203411014