Base | Representation |
---|---|
bin | 10000100000011011100… |
… | …010001011110010001001 |
3 | 11000102220122020201211222 |
4 | 100200123202023302021 |
5 | 122041103311442022 |
6 | 2225034443331425 |
7 | 144644560031324 |
oct | 20403342136211 |
9 | 4012818221758 |
10 | 1134333312137 |
11 | 3a8082645623 |
12 | 163a11b20b75 |
13 | 82c75b5429c |
14 | 3cc8b22b7bb |
15 | 1e78ec3e242 |
hex | 1081b88bc89 |
1134333312137 has 2 divisors, whose sum is σ = 1134333312138. Its totient is φ = 1134333312136.
The previous prime is 1134333312121. The next prime is 1134333312223. The reversal of 1134333312137 is 7312133334311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1110991889296 + 23341422841 = 1054036^2 + 152779^2 .
It is a cyclic number.
It is not a de Polignac number, because 1134333312137 - 24 = 1134333312121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1134333312097 and 1134333312106.
It is not a weakly prime, because it can be changed into another prime (1134339312137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567166656068 + 567166656069.
It is an arithmetic number, because the mean of its divisors is an integer number (567166656069).
Almost surely, 21134333312137 is an apocalyptic number.
It is an amenable number.
1134333312137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134333312137 is an equidigital number, since it uses as much as digits as its factorization.
1134333312137 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40824, while the sum is 35.
Adding to 1134333312137 its reverse (7312133334311), we get a palindrome (8446466646448).
The spelling of 1134333312137 in words is "one trillion, one hundred thirty-four billion, three hundred thirty-three million, three hundred twelve thousand, one hundred thirty-seven".
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