Base | Representation |
---|---|
bin | 10000100000011011100… |
… | …010100010010010110110 |
3 | 11000102220122102102022222 |
4 | 100200123202202102312 |
5 | 122041103322414332 |
6 | 2225034445322342 |
7 | 144644560564205 |
oct | 20403342422266 |
9 | 4012818372288 |
10 | 1134333404342 |
11 | 3a80826a8926 |
12 | 163a11b663b2 |
13 | 82c75b87248 |
14 | 3cc8b25323c |
15 | 1e78ec5b712 |
hex | 1081b8a24b6 |
1134333404342 has 4 divisors (see below), whose sum is σ = 1701500106516. Its totient is φ = 567166702170.
The previous prime is 1134333404317. The next prime is 1134333404357. The reversal of 1134333404342 is 2434043334311.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×11343334043422 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 283583351084 + ... + 283583351087.
It is an arithmetic number, because the mean of its divisors is an integer number (425375026629).
Almost surely, 21134333404342 is an apocalyptic number.
1134333404342 is a deficient number, since it is larger than the sum of its proper divisors (567166702174).
1134333404342 is an equidigital number, since it uses as much as digits as its factorization.
1134333404342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 567166702173.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 1134333404342 its reverse (2434043334311), we get a palindrome (3568376738653).
The spelling of 1134333404342 in words is "one trillion, one hundred thirty-four billion, three hundred thirty-three million, four hundred four thousand, three hundred forty-two".
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