Base | Representation |
---|---|
bin | 11001110010101101111000… |
… | …100110100101001011001001 |
3 | 112212122102012002010110112101 |
4 | 121302231320212211023021 |
5 | 104332020224041244223 |
6 | 1041131544225113401 |
7 | 32615336566125025 |
oct | 3162557046451311 |
9 | 485572162113471 |
10 | 113436404634313 |
11 | 33165122153902 |
12 | 1088089a488861 |
13 | 4b3b012675317 |
14 | 20024cbca3385 |
15 | d1ab1b88d4ad |
hex | 672b789a52c9 |
113436404634313 has 2 divisors, whose sum is σ = 113436404634314. Its totient is φ = 113436404634312.
The previous prime is 113436404634221. The next prime is 113436404634367. The reversal of 113436404634313 is 313436404634311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 77323672518544 + 36112732115769 = 8793388^2 + 6009387^2 .
It is a cyclic number.
It is not a de Polignac number, because 113436404634313 - 217 = 113436404503241 is a prime.
It is not a weakly prime, because it can be changed into another prime (113436404934313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56718202317156 + 56718202317157.
It is an arithmetic number, because the mean of its divisors is an integer number (56718202317157).
Almost surely, 2113436404634313 is an apocalyptic number.
It is an amenable number.
113436404634313 is a deficient number, since it is larger than the sum of its proper divisors (1).
113436404634313 is an equidigital number, since it uses as much as digits as its factorization.
113436404634313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2239488, while the sum is 46.
The spelling of 113436404634313 in words is "one hundred thirteen trillion, four hundred thirty-six billion, four hundred four million, six hundred thirty-four thousand, three hundred thirteen".
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