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113436404634313 is a prime number
BaseRepresentation
bin11001110010101101111000…
…100110100101001011001001
3112212122102012002010110112101
4121302231320212211023021
5104332020224041244223
61041131544225113401
732615336566125025
oct3162557046451311
9485572162113471
10113436404634313
1133165122153902
121088089a488861
134b3b012675317
1420024cbca3385
15d1ab1b88d4ad
hex672b789a52c9

113436404634313 has 2 divisors, whose sum is σ = 113436404634314. Its totient is φ = 113436404634312.

The previous prime is 113436404634221. The next prime is 113436404634367. The reversal of 113436404634313 is 313436404634311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77323672518544 + 36112732115769 = 8793388^2 + 6009387^2 .

It is a cyclic number.

It is not a de Polignac number, because 113436404634313 - 217 = 113436404503241 is a prime.

It is not a weakly prime, because it can be changed into another prime (113436404934313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56718202317156 + 56718202317157.

It is an arithmetic number, because the mean of its divisors is an integer number (56718202317157).

Almost surely, 2113436404634313 is an apocalyptic number.

It is an amenable number.

113436404634313 is a deficient number, since it is larger than the sum of its proper divisors (1).

113436404634313 is an equidigital number, since it uses as much as digits as its factorization.

113436404634313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2239488, while the sum is 46.

The spelling of 113436404634313 in words is "one hundred thirteen trillion, four hundred thirty-six billion, four hundred four million, six hundred thirty-four thousand, three hundred thirteen".