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1134401303201 is a prime number
BaseRepresentation
bin10000100000011111100…
…101100011001010100001
311000110002101012001001112
4100200133211203022201
5122041223213200301
62225045312513105
7144646343660105
oct20403745431241
94013071161045
101134401303201
113a8107a64291
12163a3084b795
1382c86c6b59a
143cc96289905
151e795bbe9bb
hex1081f9632a1

1134401303201 has 2 divisors, whose sum is σ = 1134401303202. Its totient is φ = 1134401303200.

The previous prime is 1134401303179. The next prime is 1134401303207. The reversal of 1134401303201 is 1023031044311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1070190250000 + 64211053201 = 1034500^2 + 253399^2 .

It is an emirp because it is prime and its reverse (1023031044311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1134401303201 - 26 = 1134401303137 is a prime.

It is not a weakly prime, because it can be changed into another prime (1134401303207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567200651600 + 567200651601.

It is an arithmetic number, because the mean of its divisors is an integer number (567200651601).

Almost surely, 21134401303201 is an apocalyptic number.

It is an amenable number.

1134401303201 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134401303201 is an equidigital number, since it uses as much as digits as its factorization.

1134401303201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1134401303201 its reverse (1023031044311), we get a palindrome (2157432347512).

The spelling of 1134401303201 in words is "one trillion, one hundred thirty-four billion, four hundred one million, three hundred three thousand, two hundred one".