Base | Representation |
---|---|
bin | 10101001000010100… |
… | …10110100111010011 |
3 | 1002021120221121021101 |
4 | 22210022112213103 |
5 | 141213043041313 |
6 | 5113355405231 |
7 | 551055235033 |
oct | 124412264723 |
9 | 32246847241 |
10 | 11344112083 |
11 | 48a1501347 |
12 | 2247153817 |
13 | 10ba2cb875 |
14 | 7988878c3 |
15 | 465db35dd |
hex | 2a42969d3 |
11344112083 has 2 divisors, whose sum is σ = 11344112084. Its totient is φ = 11344112082.
The previous prime is 11344112057. The next prime is 11344112099. The reversal of 11344112083 is 38021144311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11344112083 - 213 = 11344103891 is a prime.
It is not a weakly prime, because it can be changed into another prime (11344112383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672056041 + 5672056042.
It is an arithmetic number, because the mean of its divisors is an integer number (5672056042).
Almost surely, 211344112083 is an apocalyptic number.
11344112083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11344112083 is an equidigital number, since it uses as much as digits as its factorization.
11344112083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 11344112083 its reverse (38021144311), we get a palindrome (49365256394).
The spelling of 11344112083 in words is "eleven billion, three hundred forty-four million, one hundred twelve thousand, eighty-three".
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