Base | Representation |
---|---|
bin | 1010010100010100100011… |
… | …1111100010011010010111 |
3 | 1111011111110010020100001100 |
4 | 2211011020333202122113 |
5 | 2441330442202304221 |
6 | 40043245132401143 |
7 | 2250410450400642 |
oct | 245051077423227 |
9 | 44144403210040 |
10 | 11344233244311 |
11 | 3684075a17370 |
12 | 13327089161b3 |
13 | 6439ab3507b6 |
14 | 2b30c7192a59 |
15 | 14a1522e9926 |
hex | a5148fe2697 |
11344233244311 has 24 divisors (see below), whose sum is σ = 18452398947840. Its totient is φ = 6653509232400.
The previous prime is 11344233244291. The next prime is 11344233244313.
11344233244311 is a `hidden beast` number, since 1 + 1 + 3 + 4 + 4 + 2 + 332 + 4 + 4 + 311 = 666.
11344233244311 is nontrivially palindromic in base 10.
11344233244311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11344233244311 - 223 = 11344224855703 is a prime.
It is a super-2 number, since 2×113442332443112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11344233244313) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1848193941 + ... + 1848200078.
It is an arithmetic number, because the mean of its divisors is an integer number (768849956160).
Almost surely, 211344233244311 is an apocalyptic number.
11344233244311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
11344233244311 is a deficient number, since it is larger than the sum of its proper divisors (7108165703529).
11344233244311 is a wasteful number, since it uses less digits than its factorization.
11344233244311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3696394067 (or 3696394064 counting only the distinct ones).
The product of its digits is 82944, while the sum is 36.
It can be divided in two parts, 1134423 and 3244311, that added together give a palindrome (4378734).
The spelling of 11344233244311 in words is "eleven trillion, three hundred forty-four billion, two hundred thirty-three million, two hundred forty-four thousand, three hundred eleven".
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