Base | Representation |
---|---|
bin | 1010010100010100111011… |
… | …0010010010000000100111 |
3 | 1111011111200220010000020210 |
4 | 2211011032302102000213 |
5 | 2441331142042320201 |
6 | 40043302523430503 |
7 | 2250413040442404 |
oct | 245051662220047 |
9 | 44144626100223 |
10 | 11344330432551 |
11 | 3684115868326 |
12 | 1332735385433 |
13 | 6439c551b52c |
14 | 2b30d60512ab |
15 | 14a15aae61d6 |
hex | a514ec92027 |
11344330432551 has 32 divisors (see below), whose sum is σ = 16338190095360. Its totient is φ = 6980115828224.
The previous prime is 11344330432549. The next prime is 11344330432553. The reversal of 11344330432551 is 15523403344311.
It is an interprime number because it is at equal distance from previous prime (11344330432549) and next prime (11344330432553).
It is a cyclic number.
It is not a de Polignac number, because 11344330432551 - 21 = 11344330432549 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11344330432553) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1282270 + ... + 4932836.
It is an arithmetic number, because the mean of its divisors is an integer number (510568440480).
Almost surely, 211344330432551 is an apocalyptic number.
11344330432551 is a deficient number, since it is larger than the sum of its proper divisors (4993859662809).
11344330432551 is a wasteful number, since it uses less digits than its factorization.
11344330432551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3652175.
The product of its (nonzero) digits is 259200, while the sum is 39.
Adding to 11344330432551 its reverse (15523403344311), we get a palindrome (26867733776862).
The spelling of 11344330432551 in words is "eleven trillion, three hundred forty-four billion, three hundred thirty million, four hundred thirty-two thousand, five hundred fifty-one".
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