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113444104001 is a prime number
BaseRepresentation
bin110100110100111001…
…0111010011101000001
3101211211010002120212112
41221221302322131001
53324313142312001
6124040540505105
711124151654664
oct1515162723501
9354733076775
10113444104001
114412526a458
1219ba024b195
13a90bbc5577
1456c27916db
152e3e662cbb
hex1a69cba741

113444104001 has 2 divisors, whose sum is σ = 113444104002. Its totient is φ = 113444104000.

The previous prime is 113444103991. The next prime is 113444104031. The reversal of 113444104001 is 100401444311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113313024400 + 131079601 = 336620^2 + 11449^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113444104001 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (113444104031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56722052000 + 56722052001.

It is an arithmetic number, because the mean of its divisors is an integer number (56722052001).

Almost surely, 2113444104001 is an apocalyptic number.

It is an amenable number.

113444104001 is a deficient number, since it is larger than the sum of its proper divisors (1).

113444104001 is an equidigital number, since it uses as much as digits as its factorization.

113444104001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 113444104001 its reverse (100401444311), we get a palindrome (213845548312).

The spelling of 113444104001 in words is "one hundred thirteen billion, four hundred forty-four million, one hundred four thousand, one".