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1134441322334 = 2567220661167
BaseRepresentation
bin10000100000100001111…
…110001101011101011110
311000110012011111012222122
4100200201332031131132
5122041313434303314
62225053302342542
7144650341065005
oct20404176153536
94013164435878
101134441322334
113a8128608251
12163a4212aa52
1382c92340a48
143cc9b705c3c
151e79947728e
hex10821f8d75e

1134441322334 has 4 divisors (see below), whose sum is σ = 1701661983504. Its totient is φ = 567220661166.

The previous prime is 1134441322327. The next prime is 1134441322367. The reversal of 1134441322334 is 4332231444311.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×11344413223342 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1134441322294 and 1134441322303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 283610330582 + ... + 283610330585.

It is an arithmetic number, because the mean of its divisors is an integer number (425415495876).

Almost surely, 21134441322334 is an apocalyptic number.

1134441322334 is a deficient number, since it is larger than the sum of its proper divisors (567220661170).

1134441322334 is an equidigital number, since it uses as much as digits as its factorization.

1134441322334 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 567220661169.

The product of its digits is 82944, while the sum is 35.

Adding to 1134441322334 its reverse (4332231444311), we get a palindrome (5466672766645).

The spelling of 1134441322334 in words is "one trillion, one hundred thirty-four billion, four hundred forty-one million, three hundred twenty-two thousand, three hundred thirty-four".

Divisors: 1 2 567220661167 1134441322334