Base | Representation |
---|---|
bin | 11001110010110101010111… |
… | …101110111010000111101011 |
3 | 112212200011221021221000112122 |
4 | 121302311113232322013223 |
5 | 104332133204413304343 |
6 | 1041135354021301455 |
7 | 32616043025026634 |
oct | 3162652756720753 |
9 | 485604837830478 |
10 | 113444443103723 |
11 | 33168577706956 |
12 | 1088236256488b |
13 | 4b3b9c3b673b4 |
14 | 2002a5170288b |
15 | d1ae3c437068 |
hex | 672d57bba1eb |
113444443103723 has 2 divisors, whose sum is σ = 113444443103724. Its totient is φ = 113444443103722.
The previous prime is 113444443103627. The next prime is 113444443103737. The reversal of 113444443103723 is 327301344444311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113444443103723 - 230 = 113443369361899 is a prime.
It is a super-2 number, since 2×1134444431037232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113444443103773) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56722221551861 + 56722221551862.
It is an arithmetic number, because the mean of its divisors is an integer number (56722221551862).
Almost surely, 2113444443103723 is an apocalyptic number.
113444443103723 is a deficient number, since it is larger than the sum of its proper divisors (1).
113444443103723 is an equidigital number, since it uses as much as digits as its factorization.
113444443103723 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1161216, while the sum is 44.
The spelling of 113444443103723 in words is "one hundred thirteen trillion, four hundred forty-four billion, four hundred forty-three million, one hundred three thousand, seven hundred twenty-three".
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