Base | Representation |
---|---|
bin | 1010010100101010000110… |
… | …0100100111001010001011 |
3 | 1111012001101000100200102021 |
4 | 2211022201210213022023 |
5 | 2441424312131403022 |
6 | 40050042525145311 |
7 | 2251003635644503 |
oct | 245124144471213 |
9 | 44161330320367 |
10 | 11350014325387 |
11 | 3686572213121 |
12 | 13338609bb237 |
13 | 6443bcc69c2a |
14 | 2b34b4c96a03 |
15 | 14a38eadc7c7 |
hex | a52a192728b |
11350014325387 has 2 divisors, whose sum is σ = 11350014325388. Its totient is φ = 11350014325386.
The previous prime is 11350014325327. The next prime is 11350014325459. The reversal of 11350014325387 is 78352341005311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11350014325387 - 215 = 11350014292619 is a prime.
It is not a weakly prime, because it can be changed into another prime (11350014325327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5675007162693 + 5675007162694.
It is an arithmetic number, because the mean of its divisors is an integer number (5675007162694).
Almost surely, 211350014325387 is an apocalyptic number.
11350014325387 is a deficient number, since it is larger than the sum of its proper divisors (1).
11350014325387 is an equidigital number, since it uses as much as digits as its factorization.
11350014325387 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 11350014325387 in words is "eleven trillion, three hundred fifty billion, fourteen million, three hundred twenty-five thousand, three hundred eighty-seven".
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